# Prove that..

• Mar 8th 2010, 07:56 PM
Sanjana Das
Prove that..
$\displaystyle \frac{tan \theta +sec \theta -1}{tan \theta - sec \theta +1}= \frac{1 + sin \theta}{cos \theta}$

Kindly solve it covering all the steps ...:)
• Mar 8th 2010, 08:11 PM
Prove It
Quote:

Originally Posted by Sanjana Das
$\displaystyle \frac{tan \theta +sec \theta -1}{tan \theta - sec \theta +1}= \frac{1 + sin \theta}{cos \theta}$

Kindly solve it covering all the steps ...:)

A better idea is to show us what you have done and where you are stuck.

Hint: Convert everything into a function of sines and cosines using

$\displaystyle \tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$

and

$\displaystyle \sec{\theta} = \frac{1}{\cos{\theta}}$.
• Mar 8th 2010, 08:18 PM
Sanjana Das
When I solved my LHS was not coming equal to RHS n it was coming very long do u have any trick or something which can make it shorter ..
• Mar 9th 2010, 03:20 AM
Prove It
Quote:

Originally Posted by Sanjana Das
When I solved my LHS was not coming equal to RHS n it was coming very long do u have any trick or something which can make it shorter ..

I really hate having to repeat myself, but actually show us what you have done and where you are stuck...
• Mar 9th 2010, 04:46 AM
martingoldstein
Yes. it is.