was not quite sure how 2 solve sin((Pi*x)/3)=0 and while looking at the answer it gave 3j and j where r the j's from

regards Flowergirl5

2. Originally Posted by flowergirl5
was not quite sure how 2 solve sin((Pi*x)/3)=0 and while looking at the answer it gave 3j and j where r the j's from

regards Flowergirl5
$\sin{\frac{\pi x}{3}} = 0$

$\frac{\pi x}{3} = \arcsin{0}$

$\frac{\pi x}{3} = \pi n$, where $n$ is an integer representing the number of times you have gone around the unit circle...

$\pi x = 3\pi n$

$x = 3n$.

In this case, they have just used $j$ where I have used $n$.

3. Actually n, or j, is the number of times you have gone halfway around the unit circle. sine is 0 at any multiple of $\pi$.

(Until I saw Prove It's answer I was about to try to make "j" the imaginary unit!)