Thread: How to turn this periodic function in a quadratic equation?

I have acquired the equation:

0 = 70tanθ - 1 / 15.3125 (1+tan² θ)

I understand that I can solve this by turning it into a quadratic, just unsure how you rearrange this so that it is a quadratic.

Any help would be extremely appreciated (:

Originally Posted by eriiin

I have acquired the equation:

0 = 70tanθ - 1 / 15.3125 (1+tan² θ)

I understand that I can solve this by turning it into a quadratic, just unsure how you rearrange this so that it is a quadratic.

Any help would be extremely appreciated (:

I can't read this. Please either use LaTeX or brackets where they're needed.

Is it ?

Yes sorry, that is correct.

Start by getting a common denominator:









.


You may need technology to solve this equation.

I am unsure to whether I am doing this correctly, because I've never done a quadratic that has a number with a cube root before.

So I am guessing I need to somehow get the:

.

to a tan^2.

Any guidance to how I do this?

Perhaps you could solve it as a "cubic" instead of a "quadratic"

here's the cubic formula:

Cubic function - Wikipedia, the free encyclopedia

hope that helps

Never even seen that equation before /:
But I only have three numbers which I can use, not four, so I take it that idea isn't possible.

Originally Posted by eriiin

Never even seen that equation before /:
But I only have three numbers which I can use, not four, so I take it that idea isn't possible.

If you put:

a = 1071.875 ( )

b = 0 ( )

c = 1071.875 ( )

d = -1

so it can be solved the " " doesn't appear but it exists (this is true in all polynomials)

I hope that explains it