I have acquired the equation:
0 = 70tanθ - 1 / 15.3125 (1+tan² θ)
I understand that I can solve this by turning it into a quadratic, just unsure how you rearrange this so that it is a quadratic.
Any help would be extremely appreciated (:
I have acquired the equation:
0 = 70tanθ - 1 / 15.3125 (1+tan² θ)
I understand that I can solve this by turning it into a quadratic, just unsure how you rearrange this so that it is a quadratic.
Any help would be extremely appreciated (:
Start by getting a common denominator:
$\displaystyle 0 = 70\tan{\theta} - \frac{1}{15.3125(1 + \tan^2{\theta})}$
$\displaystyle 0 = \frac{1071.875\tan{\theta}(1 + \tan^2{\theta})}{15.3125(1 + \tan^2{\theta})} - \frac{1}{15.3125(1 + \tan^2{\theta})}$
$\displaystyle 0 = \frac{1071.875\tan{\theta}(1 + \tan^2{\theta}) - 1}{15.3125(1 + \tan^2{\theta})}$
$\displaystyle 0 = 1071.875\tan{\theta}(1 + \tan^2{\theta}) - 1$
$\displaystyle 0 = 1071.875\tan^3{\theta} + 1071.875\tan{\theta} - 1$.
You may need technology to solve this equation.
Perhaps you could solve it as a "cubic" instead of a "quadratic"
here's the cubic formula:
Cubic function - Wikipedia, the free encyclopedia
hope that helps