How do I find two numbers whose sum is 102 and quotient is 16?
let the two numbers be x and y. we want:
x + y = 102 and x/y = 16, so we get the simultaneous equations:
x + y = 102 ..................(1)
x/y = 16 ......................(2)
we will proceed by the substitution method:
from (2) we see x = 16y. substitute 16y for x in (1), we get:
16y + y = 102
=> 17y = 102
=> y = 102/17
=> y = 6
but x = 16y
=> x = 16(6)
=> x = 96
so the two numbers are 96 and 6