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Math Help - Trig help.

  1. #1
    Member integral's Avatar
    Joined
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    Trig help.

    I know the title is a bit, undiscripive...but I did not know what to call this.


    The property:
    \textrm{sin}^2\theta+\textrm{cos}^2\theta=1
    makes little since to me.
    (I know waves in physics, not algebra)

    I know that the two waves are out of phase and cause destructive interference (wave cancellation)

    But, the two waves should cancel at equilibrium (where the cos & sin waves meet ~the nods~). High presser+low presser=medium pressure (equilibrium)




    The peak for both sin^2\theta and cos^2\theta is at one, and the trough for both is at 0.
    So why not : sin^2\theta+cos^2\theta=\frac{1}{2}
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  2. #2
    Super Member bigwave's Avatar
    Joined
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    honolulu
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    Quote Originally Posted by integral View Post
    I know the title is a bit, undiscripive...but I did not know what to call this.


    The property:
    \textrm{sin}^2\theta+\textrm{cos}^2\theta=1
    makes little since to me.
    (I know waves in physics, not algebra)

    I know that the two waves are out of phase and cause destructive interference (wave cancellation)

    But, the two waves should cancel at equilibrium (where the cos & sin waves meet ~the nods~). High presser+low presser=medium pressure (equilibrium)




    The peak for both sin^2\theta and cos^2\theta is at one, and the trough for both is at 0.
    So why not : sin^2\theta+cos^2\theta=\frac{1}{2}
    well I don't know physics but the sin^2\theta + cos^2\theta = 1
    is an identity using a unit circle where 1 is the hypotenuse or radius that is fixed
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  3. #3
    MHF Contributor
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    Hi integral,

    they only ever meet "half-way", so they always add to 1.
    Attached Thumbnails Attached Thumbnails Trig help.-sin-2-x-cos-2-x-1.jpg  
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