Trigonometric addtion/subtraction & half identity problem.

**F.A.S.T.** · March 1st 2010, 10:29 AM

Sorry, this problem is killing me. Normally it would be easy, but I'm havein problems breaking the radian mesure 11pie/12. Here is the problem.

Using the radian mesure of 11pie/12, choose sine, cosine, or tangent and develop the exact value of that measure using the angle addition or subtraction identity and the half angle identity. Show the work below. The answers you come up with for both should be equal, even hough they may not be written in the same form.

Thank you!

**running-gag** · March 1st 2010, 10:49 AM

Hi

You know the value for $\cos \left(\frac{\pi}{6}\right)$ and $\sin \left(\frac{\pi}{6}\right)$

Using $\cos(2a) = 2 \cos^2a-1 = 1 - 2 \sin^2a$ with $a = \frac{\pi}{12}$ will give you the exact values for $\cos \left(\frac{\pi}{12}\right)$ and $\sin \left(\frac{\pi}{12}\right)$

And $\cos \left(\frac{11\pi}{12}\right) = \cos \left(\pi-\frac{\pi}{12}\right) = -\cos \left(\frac{\pi}{12}\right)$

$\sin \left(\frac{11\pi}{12}\right) = \sin \left(\pi-\frac{\pi}{12}\right) = \sin \left(\frac{\pi}{12}\right)$

**F.A.S.T.** · March 1st 2010, 04:22 PM

^Well that answer is good, how did you/do you get it into the from of: cos(x+y)=cosXcosY-sinXsinY?
I got the Half angle for cos.
The equation finishes like so:

The two answers should be equal...
Sorry the first sin should be a cos...

**F.A.S.T.** · March 1st 2010, 05:07 PM

Never mind, I got it...

Thanks!

Thread: Trigonometric addtion/subtraction & half identity problem.

LinkBack

Thread Tools

Display

Trigonometric addtion/subtraction & half identity problem.

Similar Math Help Forum Discussions

trigonometric identity problem

addition or subtraction for cofunction identity

Trigonometric Angle additoin/subtraction/half angle identity's.

Trigonometric Identity Problem

[SOLVED] half-angle identity problem

Search Tags