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Math Help - if x<-[o;360] ...

  1. #1
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    Question if x<-[o;360] ...

    if x<-[o;360] solve for x
    1/sin(x-20)=-2.32
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  2. #2
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    Hello, rionariona!

    \text{If }x \in [0^o,\:360^o],\:\text{ solve for }x\!:\;\;\frac{1}{\sin(x-20)} \:=\:-2.32

    We have: . \sin(x-20) \;=\;-\frac{1}{2.32}

    Then: . x-20 \;=\;\arcsin\left(-\frac{1}{2.32}\right) \;\approx\;-25.53^o

    Hence: . x-20 \;=\;\begin{Bmatrix}205.53^o \\ 334.47^o\end{Bmatrix}


    Therefore: . x \;=\;\begin{Bmatrix}225.53^o \\ 354.47^o \end{Bmatrix}

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