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Thread: solve for x

  1. February 28th 2010, 01:22 PM #1
    rionariona
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    Question solve for x

    if -180<=x<=180 solve
    6-10cosx=3sin^2x
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  2. February 28th 2010, 01:37 PM #2
    e^(i*pi)
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    Quote Originally Posted by rionariona View Post
    if -180<=x<=180 solve
    6-10cosx=3sin^2x
    \sin^2(x) = 1 - \cos^2(x)

    6-10 \cos(x) = 3 - 3\cos^2(x) which is a quadratic in cos(x)

    Put into the form ax^2+bx+c=0 and solve using the quadratic formula
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