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Math Help - trig assignment due today please help

  1. #1
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    Unhappy trig assignment due today please help

    ive been tryn for abt an hour now nd cant seem to figure it out:

    if 2ptanx+1=p, determine the value of cosx in terms of p
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by rionariona View Post
    ive been tryn for abt an hour now nd cant seem to figure it out:

    if 2ptanx+1=p, determine the value of cosx in terms of p
    note that this means \tan x = \frac {p - 1}{2p} (note that p cannot be zero, so this makes sense).

    Recall that \tan x = \frac {\sin x}{\cos x} = \pm \frac {\sqrt{ 1 - \cos x}}{\cos x}

    plug this into the first equation and solve for \cos x. This is pretty much all the help you can get since this is a graded assignment.
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  3. #3
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    i was told to solve for tanx and then draw the diagram.. the triangle has x=2p, y=p-1, and i solved r=5p^2-2p+1... that makes cos= 2p/ 5p^2-2p+1... nd im lost after that
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  4. #4
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    Quote Originally Posted by rionariona View Post
    i was told to solve for tanx and then draw the diagram.. the triangle has x=2p, y=p-1, and i solved r=5p^2-2p+1... that makes cos= 2p/ 5p^2-2p+1... nd im lost after that
    You have cos(x) in terms of p, surely you needn't go further?
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  5. #5
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    your quite right hey, silly me... thanx for the help tho
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