ive been tryn for abt an hour now nd cant seem to figure it out:

if 2ptanx+1=p, determine the value of cosx in terms of p

2. Originally Posted by rionariona
ive been tryn for abt an hour now nd cant seem to figure it out:

if 2ptanx+1=p, determine the value of cosx in terms of p
note that this means $\tan x = \frac {p - 1}{2p}$ (note that p cannot be zero, so this makes sense).

Recall that $\tan x = \frac {\sin x}{\cos x} = \pm \frac {\sqrt{ 1 - \cos x}}{\cos x}$

plug this into the first equation and solve for $\cos x$. This is pretty much all the help you can get since this is a graded assignment.

3. i was told to solve for tanx and then draw the diagram.. the triangle has x=2p, y=p-1, and i solved r=5p^2-2p+1... that makes cos= 2p/ 5p^2-2p+1... nd im lost after that

4. Originally Posted by rionariona
i was told to solve for tanx and then draw the diagram.. the triangle has x=2p, y=p-1, and i solved r=5p^2-2p+1... that makes cos= 2p/ 5p^2-2p+1... nd im lost after that
You have cos(x) in terms of p, surely you needn't go further?

5. your quite right hey, silly me... thanx for the help tho