Hey there,

I have this problem that I've been able to solve, but only after what seems like an excessive amount of working. Was wondering if anyone knows a quicker way to go about it?

Given that $\displaystyle t=tan\left (\frac{x}{2}\right )$ show that $\displaystyle sin(x)=\frac{2t}{1+t^2}$

I've done this by first showing that $\displaystyle cos(x)=\frac{1-t^2}{1+t^2}$, but I'm sure there must be a shorter way, or something simple that I'm missing?

THanks