How would you derive the relationships between the trigonometric functions and the inverse trigonometric functions, such as:

$\displaystyle \sin(\arccos(x)) = \sqrt{1 - x^2}$

$\displaystyle \sin(\arctan(x)) = \frac{x}{\sqrt{1 + x^2}}$

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- Feb 19th 2010, 07:03 AMNOX AndrewTrigonometric Functions and Inverse Trigonometric Functions
How would you derive the relationships between the trigonometric functions and the inverse trigonometric functions, such as:

$\displaystyle \sin(\arccos(x)) = \sqrt{1 - x^2}$

$\displaystyle \sin(\arctan(x)) = \frac{x}{\sqrt{1 + x^2}}$ - Feb 19th 2010, 10:32 AMrunning-gag
- Feb 19th 2010, 10:37 AMrunning-gag