Am I doing this right?

**Tall Jessica** · February 18th 2010, 11:45 AM

It's a simplification. I'm supposed to simplify so that only one variable is present at the end.

x = [sin(A+B)/2]/sin(A/2)

Here's what I've done so far...

x = 2[sin(A+B)] / 2[sin(A)

x = sin(A + B) / sin(A)

am I totally off....?

Thank you!

**skeeter** · February 18th 2010, 04:37 PM

Originally Posted by Tall Jessica

It's a simplification. I'm supposed to simplify so that only one variable is present at the end.

x = [sin(A+B)/2]/sin(A/2)

Here's what I've done so far...

x = 2[sin(A+B)] / 2[sin(A)

x = sin(A + B) / sin(A)

am I totally off....?

Thank you!

is the equation ...

$x = \frac{\sin\left(\frac{A+B}{2}\right)}{\sin\left(\f rac{A}{2}\right)}$

or

$x = \frac{\frac{\sin(A+B)}{2}}{\sin\left(\frac{A}{2}\r ight)}$

or something else ?

**Tall Jessica** · February 18th 2010, 05:07 PM

Originally Posted by skeeter

is the equation ...

$x = \frac{\sin\left(\frac{A+B}{2}\right)}{\sin\left(\f rac{A}{2}\right)}$

or

$x = \frac{\frac{\sin(A+B)}{2}}{\sin\left(\frac{A}{2}\r ight)}$

or something else ?

The first one. Thanks :-)

**skeeter** · February 18th 2010, 05:51 PM

I don't know if the original expression can be "simplified" any more than it is already. You're not going to get an expression with only A or B alone unless there is a known relationship between A and B.

I tried using the half-angle formula for sine ...

$\sin\left(\frac{A+B}{2}\right) = \pm \sqrt{\frac{1 - \cos(A+B)}{2}}$

$\sin\left(\frac{A}{2}\right) = \pm \sqrt{\frac{1 - \cos{A}}{2}}$

doing the division ...

$\pm \sqrt{\frac{1 - \cos(A+B)}{1 - \cos{A}}}$

I also did the sum expansion for $\sin\left(\frac{A}{2} + \frac{B}{2}\right)$ , divided by $\sin\left(\frac{A}{2}\right)$ and got the following expression ...

$\cos\left(\frac{B}{2}\right) + \cot\left(\frac{A}{2}\right) \sin\left(\frac{B}{2}\right)$

not much there as far as "simplification" goes, either.

Is there more to this problem that you haven't posted?

**Tall Jessica** · February 18th 2010, 06:20 PM

Well... I probably copied it wrong. I'll check tomorrow.

Thank you and sorry!

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Am I doing this right?