It's a simplification. I'm supposed to simplify so that only one variable is present at the end.

x = [sin(A+B)/2]/sin(A/2)

Here's what I've done so far...

x = 2[sin(A+B)] / 2[sin(A)

x = sin(A + B) / sin(A)

am I totally off....?

Thank you!

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- February 18th 2010, 12:45 PM #1

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## Am I doing this right?

It's a simplification. I'm supposed to simplify so that only one variable is present at the end.

x = [sin(A+B)/2]/sin(A/2)

Here's what I've done so far...

x = 2[sin(A+B)] / 2[sin(A)

x = sin(A + B) / sin(A)

am I totally off....?

Thank you!

- February 18th 2010, 05:37 PM #2

- February 18th 2010, 06:07 PM #3

- Joined
- Dec 2008
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- 21

- February 18th 2010, 06:51 PM #4
I don't know if the original expression can be "simplified" any more than it is already. You're not going to get an expression with only A or B alone unless there is a known relationship between A and B.

I tried using the half-angle formula for sine ...

doing the division ...

I also did the sum expansion for , divided by and got the following expression ...

not much there as far as "simplification" goes, either.

Is there more to this problem that you haven't posted?

- February 18th 2010, 07:20 PM #5

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