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Math Help - [SOLVED] Please help find an inverse

  1. #1
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    [SOLVED] Please help find an inverse

    I was hoping for some help finding the inverse of the function:
     h(x)=cos^2x+2cosx+1
    I am stuck at the point where I have:
    y-1=(cosx)(cosx)+cosx+cosx

    I was hoping to find a way to combine the cosine terms, so that I can just take the arc-cosine of both sides and be done, but can't figure out how.
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  2. #2
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    Quote Originally Posted by Dotdash13 View Post
    I was hoping for some help finding the inverse of the function:
     h(x)=cos^2x+2cosx+1
    I am stuck at the point where I have:
    y-1=(cosx)(cosx)+cosx+cosx

    I was hoping to find a way to combine the cosine terms, so that I can just take the arc-cosine of both sides and be done, but can't figure out how.
    note that \cos^2{x} + 2\cos{x} + 1 = (\cos{x} + 1)^2
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