Question on trig equation

**ConfusedMath** · February 12th 2010, 06:40 PM

9sin^-1x=3pie

I used the inverse property for sin and get x=9sin3pie but am stuck from there.

**Grandad** · February 13th 2010, 12:53 AM

Hello ConfusedMath

Originally Posted by ConfusedMath

9sin^-1x=3pie

I used the inverse property for sin and get x=9sin3pie but am stuck from there.

You have the $9$ in the wrong place.

$9\sin^{-1}(x) = 3\pi$

$\Rightarrow \sin^{-1}(x) = \frac{3\pi}{9}=\frac{\pi}3$

$\Rightarrow x = \sin\left(\frac{\pi}3\right)=\frac{\sqrt3}{2}$

Grandad

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