# Question on trig equation

• Feb 12th 2010, 06:40 PM
ConfusedMath
Question on trig equation
9sin^-1x=3pie

I used the inverse property for sin and get x=9sin3pie but am stuck from there. (Thinking)
• Feb 13th 2010, 12:53 AM
Hello ConfusedMath
Quote:

Originally Posted by ConfusedMath
9sin^-1x=3pie

I used the inverse property for sin and get x=9sin3pie but am stuck from there. (Thinking)

You have the $9$ in the wrong place.

$9\sin^{-1}(x) = 3\pi$

$\Rightarrow \sin^{-1}(x) = \frac{3\pi}{9}=\frac{\pi}3$

$\Rightarrow x = \sin\left(\frac{\pi}3\right)=\frac{\sqrt3}{2}$