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Math Help - Please can you check my answer?

  1. #1
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    Please can you check my answer?



    Here I am trying to find the general solution to what is on top of the page. Have I done this correctly? Thanks if you can check this for me
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  2. #2
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    e^(i*pi)'s Avatar
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    You introduced t in the second line without explaining it's relation to \theta.

    It would be better if you could explain how they are related
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  3. #3
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    Quote Originally Posted by e^(i*pi) View Post
    You introduced t in the second line without explaining it's relation to \theta.

    It would be better if you could explain how they are related
    They are related through a right angled triangle where

    sin\theta = \frac{O}{H} , cos\theta = \frac{A}{H} and tan\theta = \frac{O}{A}

    where O, the opposite, is 2t
    where A, the adjacent, is 1-t^2
    and H, the hypotenuse, is 1+t^2

    I missed out the explanation on this (which I think is best shown when the triangle is actually drawn out) but will keep it in mind whenever I do this type of question in the future.
    Otherwise, would you believe that my working is correct?
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