I'm stumped on a physics question here, which goes:
The vector, v, has the following components: Vx= +65.0 m/s , Vy= -120 m/s
Calculate the magnitude and polar positive direction of the vector, v.
(Sorry, but please assume the "v" as the v with an arrow over it, and the x and y in Vx and Vy as subscripts...)
So, using that information, I graphed out a triangle and found the hypotenuse.
To get the polar positive direction, I believe I need the degree of the angle that the red arrow is pointing to. But how do I find that angle?
I've tried using tan=opp/adj, or tan=Vy/Vx, but I get a negative number as my answer. Could somebody please help me with this question?
Thanks a lot.
(Also, am I right in thinking that the hypotenuse is the magnitude of the vector?)
for an angle in quad IV ...