log54 (to the base of 10) + log2(to the base of 2)-1/2log81(to the base of 10) please can you answer it.. tnx
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Originally Posted by donniemsb12 log54 (to the base of 10) + log2(to the base of 2)-1/2log81(to the base of 10) please can you answer it.. tnx $\displaystyle \log_{10} 54 + \log_2 2 - 0.5 \log_{10} 81 = \log_{10} 9\cdot6 + 1 - 0.5 \log_{10} 9^2 $$\displaystyle = \log_{10} 9 + \log_{10} 6 + 1 - \log_{10} 9 = 1 + \log_{10} 6$
thanks
4(log2(to the base of 10))^2 + log16( to the base of ten)log25(to the base of ten)+4(log5(to the base of10))^2 eto pa paki ulet... tnx....
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