log54 (to the base of 10) + log2(to the base of 2)-1/2log81(to the base of 10)

2. Originally Posted by donniemsb12
log54 (to the base of 10) + log2(to the base of 2)-1/2log81(to the base of 10)

$\log_{10} 54 + \log_2 2 - 0.5 \log_{10} 81 = \log_{10} 9\cdot6 + 1 - 0.5 \log_{10} 9^2$ $= \log_{10} 9 + \log_{10} 6 + 1 - \log_{10} 9 = 1 + \log_{10} 6$