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Math Help - please help me (logarithm)

  1. #1
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    please help me (logarithm)

    log54 (to the base of 10) + log2(to the base of 2)-1/2log81(to the base of 10)

    please can you answer it.. tnx
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  2. #2
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    Quote Originally Posted by donniemsb12 View Post
    log54 (to the base of 10) + log2(to the base of 2)-1/2log81(to the base of 10)

    please can you answer it.. tnx
    \log_{10} 54 + \log_2 2 - 0.5 \log_{10} 81 = \log_{10} 9\cdot6 + 1 - 0.5 \log_{10} 9^2 = \log_{10} 9 + \log_{10} 6 + 1 - \log_{10} 9 = 1 + \log_{10} 6
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  3. #3
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    thanks
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  4. #4
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    4(log2(to the base of 10))^2 + log16( to the base of ten)log25(to the base of ten)+4(log5(to the base of10))^2


    eto pa paki ulet...

    tnx....
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