• Feb 6th 2010, 05:47 PM
Sarnick
Hi all,
Just joined the site and have a question. I don't know if this is a question for the trigonometry forum but I'm not sure where to ask. I have a question about GPS coordinates (degrees, minutes and seconds). I have to find a spot and need to add 73 minutes to the minutes of the coordinates 071* 59.922 and add 10 minutes to the minutes of the coordinates 40* 58.647 to come up with the correct coordinates but I was never very good at math. I know once the minutes exceed 60 you have to add to the degrees but I'm having trouble with the conversion. Any help would be greatly appreciated.

Thanks
• Feb 6th 2010, 06:01 PM
VonNemo19
Quote:

Originally Posted by Sarnick
Hi all,
Just joined the site and have a question. I don't know if this is a question for the trigonometry forum but I'm not sure where to ask. I have a question about GPS coordinates (degrees, minutes and seconds). I have to find a spot and need to add 73 to the minutes of the coordinates 071* 59.922 and add 10 to the minutes of the coordinates 40* 58.647 to come up with the correct coordinates but I was never very good at math. I know once the minutes exceed 60 you have to add to the degrees but I'm having trouble with the conversion. Any help would be greatly appreciated.

Thanks

What do you mean by 071* 59.922? Give it to me in word form.
• Feb 6th 2010, 06:17 PM
Sarnick
Thanks for replying; it would be 71 degress, 59 minutes and 922 seconds West and 40 degrees, 58 minutes and 647 seconds North. The seconds don't matter for this problem.
• Feb 6th 2010, 06:25 PM
VonNemo19
Quote:

Originally Posted by Sarnick
Thanks for replying; it would be 71 degress, 59 minutes and 922 seconds North and 40 degrees, 58 minutes and 647 seconds west. The seconds don't matter for this problem.

OK. $\displaystyle 73'+59'=132'$. Note that $\displaystyle 132'\div60'=2^\circ\frac{1}{5}^\circ$

But $\displaystyle \frac{1}{5}^\circ=\frac{60}{5}'=12'$

Can you see where I'm going?
• Feb 6th 2010, 06:53 PM
Sarnick
Thanks for trying to help but your confusing me more. LOL! Here's an example; If the number you had to add to the West coords was 62 then the answer would be 73 degrees, 01 minutes and 922 seconds. I was never any good at math and thanks for your time.

Does this help?
• Feb 6th 2010, 07:06 PM
VonNemo19
Quote:

Originally Posted by Sarnick
Thanks for trying to help but your confusing me more. LOL! Here's an example; If the number you had to add to the West coords was 62 then the answer would be 73 degrees, 01 minutes and 922 seconds. I was never any good at math and thanks for your time.

Does this help?

I'll try again...(Wink)

$\displaystyle 79^\circ{\color{red}59'}92.2''+{\color{red}73'}=79 ^\circ{\color{red}132'}92.2''$.

Now, understand that there are $\displaystyle 60'$ in $\displaystyle 1^\circ$, so we have to make the thing proper by determining how many minutes we can get out of 132 seconds.

The answer is 2 minutes with 12 seconds left over, so our final answer:

$\displaystyle 81^\circ{\color{red}12'}92.2''+{\color{red}73'}$
• Feb 6th 2010, 07:36 PM
Sarnick
OK so would it be 073* 12.922?

The answer is going to be 073* ?.922

81* is to high. The coords are going to be 073* something.922

• Feb 6th 2010, 07:52 PM
VonNemo19
Quote:

Originally Posted by Sarnick
OK so would it be 073* 12.922?

The answer is going to be 073* ?.922

81* is to high. The coords are going to be 073* something.922

So, we have $\displaystyle 71^\circ59.992'+73'=71^\circ132.992'=73^\circ12.99 2'$