the same way?
b^2= a^2+c^2-2ac Cos B
c^2= b^2+a^2-2ba Cos C
you got angle A wrong too, check your calculations
Cos A= (5^2-8^2-7^2)/(-2(8)(7))
a=5m , b=8m , c=7m
a^2= b^2+c^2-2bc Cos A
(5)^2= (8)^2+(7)^2-2(8)(7) Cos A
Cos A= 5^2-8^2+7^2/-2(8)(7)
Cos A= 10/-112
Angle A= -0.0898
Angle A= 95 Degrees 9 minutes
How to find other B & C angle?
This is what i work out but stuck.........
a/Sin A = b/SinB
5/Sin 95 Degrees 9 minutes = 8/Sin B
Sin B = (8)(Sin 95 Degrees 9 minutes)/5
Sin B = 1.5939
Problem is i calculate using sin^-1...
Thanks much