Originally Posted by

**zachb** I had trig last semester, but I seriously need to review what I "learned".

Anyway, I need help simplifying this experssion:

tan(sin^-1x)

by following the example in my book (because my professor hasn't even show us how to do this!), this is how far I've gotten:

tan(sin^-1x)

y = sin^-1x

sin y = x and -n/2 < y < n/2

1 + cot^2y = csc^2y . . . by the pythagorean identities

csc y = (square root of)1 + x^2 . . . I'm pretty sure I messed up on this step

tan(sin^-1x) = tan y = 1/csc y = 1/ (square root of)1 + X^2

Is that correct, and if not, can someone please help me out?