Hi guys, I shall ask for your help again Ok, so here's the equation: Tan^3x + sinxsecx-sinxcosx = tanxsecx + sinx Secx-cosx
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Hi purplesky $\displaystyle \frac{tan^{3}x+sin(x)~sec(x)-sin(x)cos(x)}{sec(x)-cos(x)}$ $\displaystyle =\frac{tan^{3}x}{sec(x)-cos(x)}+\frac{sin(x)[sec(x)-cos(x)]}{sec(x)-cos(x)}$ ...
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