Originally Posted by

**protractor** hello,

I'm currently studying problems involving forces in equilibrium.

In my text book, I'm examining 3 different ways of solving the same problem. In this particular question, you have to find the values of T1 and T2.

In the part I'm on now, you solve it by drawing a **Triangle of Force**.

I understand how to do the **Vectors**, but I don't know how they've worked out the **angles in the triangle**. Could anyone manage to explain this to me at all?

I have a picture I've drawn on "Paint" of the original 3 forces, plus the triangle of force, and I've tried to paste it here, but it doesn't seem to be working, and I'm not sure how to do it.

To describe it, the force diagram consists of an **object of mass 12 Kg,**suspended by **2 strings called T1 and T2**. **String T1 i**s sort of pointing upwards and leftwards, forming an angle of **27 degrees** **with the horizon** at the top. **String T2** is pointing upwards and rightwards, forming an angle of **38 degrees with the horizon** at the top. At the bottom of the 2 strings, where they meet, hangs the **object of 12gN.**

I'm sorry I can't manage to get the diagram put up here. I'll have to try and learn how to do it.

Oh, actually I think I have managed to upload a picture of the original forces. Now I'm going to try and attach a picture of their triangle of forces.

IN THE TRIANGLE THAT I CAN NOW SEE UNDER MY POST, THE ANGLES IN THEIR FORCE TRIANGLE ARE:

BOTTOM LEFT - 52 degrees

RIGHT - 65 degrees

TOP - 63 degree

The vectors in the triangle of force are - VERTICAL ONE ON LEFT = 12g. ONE AT TOP = T1. ONE STARTING AT BOTTOM AND SLOPING UPWARDS AND RIGHTWARDS = T2[/U]

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