Thread: nid help from this

1. nid help from this

A Baguio city road is inclined 20degree to the horizontal. If a man jogs 500m along this road, how high above is his starting point?

Anyone know how to diagram and solve this problem? nid help please

2. Originally Posted by sherwin156
A Baguio city road is inclined 20degree to the horizontal. If a man jogs 500m along this road, how high above is his starting point?

Anyone know how to diagram and solve this problem? nid help please
Draw a horizontal line to signify the starting point. From this line draw an angle of 20 degrees from it.

From the end of the horizontal line draw a vertical line (so that a right-angle is formed with the horizontal) until it reaches the angle line.

You should now have a right-angled triangle to work with. We know that the hypotenuse is 500m and the angle is 20 degrees. To find the height label the vertical line h and note this opposite the 20degree angle.

We now have an angle and the hypotenuse while needing to find the opposite. Can you recall a trig ratio to use in this situation

3. Sin= opp. side/ hypotenuse?

4. Almost correct.

It's actually

$\sin{\theta} = \frac{\textrm{Opposite}}{\textrm{Hypotenuse}}$.

So substituting in your values gives

$\sin{20^\circ} = \frac{h}{500\,\textrm{m}}$.

Solve for $h$.

5. thx i get it thx to all of you...

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A hiker is walking up a mountainwith an angle of elevation of 32degrees for 250m. For the next 120m the angle of elevation changes to 39degrees .how high above his starting point is he by now?

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