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  1. #1
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    nid help from this

    A Baguio city road is inclined 20degree to the horizontal. If a man jogs 500m along this road, how high above is his starting point?

    Anyone know how to diagram and solve this problem? nid help please
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  2. #2
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    Quote Originally Posted by sherwin156 View Post
    A Baguio city road is inclined 20degree to the horizontal. If a man jogs 500m along this road, how high above is his starting point?

    Anyone know how to diagram and solve this problem? nid help please
    Draw a horizontal line to signify the starting point. From this line draw an angle of 20 degrees from it.

    From the end of the horizontal line draw a vertical line (so that a right-angle is formed with the horizontal) until it reaches the angle line.

    You should now have a right-angled triangle to work with. We know that the hypotenuse is 500m and the angle is 20 degrees. To find the height label the vertical line h and note this opposite the 20degree angle.

    We now have an angle and the hypotenuse while needing to find the opposite. Can you recall a trig ratio to use in this situation
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    Sin= opp. side/ hypotenuse?
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  4. #4
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    Almost correct.

    It's actually

    \sin{\theta} = \frac{\textrm{Opposite}}{\textrm{Hypotenuse}}.


    So substituting in your values gives

    \sin{20^\circ} = \frac{h}{500\,\textrm{m}}.


    Solve for h.
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  5. #5
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    thx i get it thx to all of you...
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