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Math Help - finding trigonometry of angles

  1. #1
    zachary7
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    finding trigonometry of angles

    I was given an assignment and I really need some help. I've not been doing algebra in the other school and have no idea how to do applications and concepts. The paper is special right triangles and I must "find each missing length. Round to the nearest tenth if necessary." My question is HOW do you solve these triangle problems?????????
    Many thanks to anyone who can offer a hand.
    Zach
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  2. #2
    Super Member Aryth's Avatar
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    Quote Originally Posted by zachary7 View Post
    I was given an assignment and I really need some help. I've not been doing algebra in the other school and have no idea how to do applications and concepts. The paper is special right triangles and I must "find each missing length. Round to the nearest tenth if necessary." My question is HOW do you solve these triangle problems?????????
    Many thanks to anyone who can offer a hand.
    Zach
    Well, there are two particular special right triangles:

    One is the 30,60,90, which are the angles of the triangles:





    Where x = 1, y = sqrt(3), and r = 2 r is the resultant or the hypotenuse as you'll see it.

    The other special triangle is the 45-45-90 triangle:


    Where x = 1, y = 1, and r = sqrt(2)

    For any other right triangles, you can use these formulas to solve for x,y,r and the angles:

    cos(@) = x/r
    sin(@) = y/r
    tan(@) = y/x

    If r = 1, then:

    cos(@) = x
    sin(@) = y
    tan(@) = y/x

    Or if you have just the lengths, you can use this:

    x^2 + y^2 = r^2

    This is called the Pythagorean Theorem.

    Where @ is the angle in degrees or radians, x is the horizontal component, otherwise known as the bottom leg, y is the vertical component, known as the upper leg, and r is the hypotenuse, it is always the side that slants from one leg to another. I hope this helps.
    Last edited by Aryth; March 15th 2007 at 07:00 PM.
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