The attached shows the angle to be 65° , but that now is$\displaystyle x $in radians where$\displaystyle 0 < x < \frac{1}{2}\pi$.

Then the normal reaction depend on$\displaystyle x$; we let the normal reaction from the lift have magnitude$\displaystyle fr(x)$newtons. We assume that the domain of$\displaystyle f$ $\displaystyle fr $is$\displaystyle (0,\frac{1}{2} \pi]$

1) Use a triangle of force to show that the$\displaystyle f$has the rule

$\displaystyle fr(x) = \frac{1.5}{sin x}$

2) find the value of$\displaystyle fr(\frac{1}{2} \pi)$and explain why this value makes sense in situation modelled