Angle's and stuff....

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• Mar 15th 2007, 04:04 AM
PR0DiGY
Angle's and stuff....
Hai guys, my first post here, heard this site off a mate.

K I need to hand this in, in like 2 days so any help will be very appreciated thank you. I'm in like Low math's so dont laugh lol...My friend did his, and he had like 5 pages of working out :|, I have included one image, which is all that you guys need to work your magic, if you want an example of what I have gotten upto so far, Just say and I will scan them too but I dont think any of you need it, its very easy but im just very **** at math's :(

Btw in Australia we have Math's A, B and C.

I can do Part A which is just the drawing, Just need help on part B and C please, thanks so much for reading :D

http://img137.imageshack.us/img137/2714/picturegk9.jpg
• Mar 15th 2007, 04:57 AM
earboth
Quote:

Originally Posted by PR0DiGY
Hai guys, my first post here, ...

I can do Part A which is just the drawing, Just need help on part B and C please, thanks so much for reading :D
...

Hello,

to B:

You have to calculate the volume of the concrete (without considering that concrete will shrink when it is hardening:) )

slab: the slab is a cuboid with the base area 7m * 7m = 49 m² and the height 0.1 m. Therefore the volume of the slabe is: V_s = 4.9 m³

footing: The measures are not clear: Is the footing 0.35 m deep or is it 0.6 m deep. I've done both possibilities.
To get the volume you first have to calculate the base area. The simplest method is to subtract an inner square from the constant outer square (see attachment)
0.6 m deep: a = 49m² - 6.3*6.3m² = 9.31 m²
V = 9.31m² * 0.6m = 5.586 m³

0.35 m deep: a = 49m² - 5.8*5.8m² = 15.36 m²
V = 15.36m² * 0.35m = 5.376 m³

price: (4.9m³ + 5.586m³) * \$120/m³ = \$1258.32 or
price: (4.9m³ + 5.376m³) * \$120/m³ = \$1233.12

EB
• Mar 15th 2007, 01:11 PM
PR0DiGY
:| WOW THANKS!

And footings are .6m deep and .35 wide, thanks so much :)