Use Pythagorean identities to write the expression as an integer.
tan^2 4β - sec^2 4β
Please help me i dont know what to do...
What are you trying to do? Just simplify?
$\displaystyle \frac{\cot^2\alpha-4}{\cot^2\alpha-\cot\alpha-6}$
make $\displaystyle x =\cot\alpha $
$\displaystyle \frac{x^2-4}{x^2-x-6}$
$\displaystyle \frac{(x-2)(x+2)}{(x-3)(x-2)}$
$\displaystyle \frac{x+2}{x-3}$
$\displaystyle \frac{\cot\alpha+ 2}{\cot\alpha -3}$
Quick Question for this expression:
$\displaystyle 5sin^2(\theta/4)+5cos^2(\theta/4)$
how do u get rid of the $\displaystyle (\theta/4)$ to make it equal to 5? i understand that it will be equal to 5
is it that i dont have to worry about the theta and jus simplify it equal to five
i.e. $\displaystyle 5(sin^2(\theta/4)+cos^2(\theta/4))$
$\displaystyle 5(1)$