$\displaystyle \frac{csc\theta+1}{(1/sin^2\theta)+csc\theta}$ is the answer to this $\displaystyle sin^2\theta$
Last edited by purplec16; Jan 26th 2010 at 07:56 PM.
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Use the fact $\displaystyle \csc\theta = \frac{1}{\sin\theta}$
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