1. ## Trigs and logs

2. Originally Posted by Tarwamin
So, you need help with problem 6? what have you tried?

3. I tried it wen it was secx but my teacher told me to do cscx so i dont noe how to do that

4. Originally Posted by Tarwamin
I tried it wen it was secx but my teacher told me to do cscx so i dont noe how to do that
Start that one by working with the left hand side because it is more complicated.

$\displaystyle \sin{x}+\sin{x}\cot^2{x}=\csc{x}$

Factor out a sine

$\displaystyle \sin{x}(1+\cot^2{x})=\csc{x}$

But, we know that $\displaystyle 1+\cot^2{x}=\csc^2{x}$

So, now we get

$\displaystyle \sin{x}\csc^2{x}=\csc{x}$

But, we also know that [tex]\frac{1}{\csc^2{x}}=frac{1}{\sin^2{x}}[/mATH]

So, now we get

$\displaystyle \sin{x}\frac{1}{\sin^2{x}}=\csc{x}$

You should be able to take it from here.

5. thank you so much!