Hi, this trigonometric inequality was on our test, and I didn't know how to solve it.
sin(pi/2(x)) < (x-2)^3-1
The cycle for hte sine function is 1, and I know one of the points of intersection is 3, but I do not know how to solve for the other two points of intersection for the inequality.
Your help is greatly appreciated!
my assumption on this. is that since it is an inequality you have 2 graphs
and the answer is a particular area between the two
you might want to look at this.....
make sure I have plugged it in correct
hope this helps...