sqrt3 can be a positive or negative number so there are solutions in all quadrants? My book says only the third and fourth. I don't need any further work done.
sqrt3 can be a positive or negative number so there are solutions in all quadrants? My book says only the third and fourth. I don't need any further work done.
hi
your book is right . $\displaystyle \sin 4x=-\frac{\sqrt{3}}{2}$ and sin is negative in teh 3rd and 4th quadrant .
Note that $\displaystyle x=\sqrt{4}\Rightarrow x=2$ but if $\displaystyle x^2=4\Rightarrow x=\pm 2$