Solve the equation:
π-3arccosθ=0
all i understand is arccosθ=0 means cos0=θ
but i'm getting confused when there is a value multiplying arc
the answer is arccosθ=π/3,θ=cosπ/3 =1/2
this is a poorly posed equation ... the input for an inverse trig function is normally a trig ratio, not an angle, because the output of the arccos function is an angle. $\displaystyle \theta$ represents an angle.
using $\displaystyle x$ instead of $\displaystyle \theta$ ...
$\displaystyle \pi - 3\arccos{x} = 0$
$\displaystyle \arccos{x} = \frac{\pi}{3}$
$\displaystyle x = \cos\left(\frac{\pi}{3}\right) = \frac{1}{2}$