# Thread: Trigo graph stucked @ b

1. ## Trigo graph stucked @ b

a) Sketch the graph of $\displaystyle y=|2cosx|+1$ for 0 ≤ x ≤ 2$\displaystyle \pi$, stating the coordinates of the turning points.

b) State the number of solutions for the equation $\displaystyle |2cosx|+1 = \frac{x}{2}$ for 0 ≤ x ≤ 2$\displaystyle \pi$
I have already solved for part a, having problems with part b...

I am guessing that we have to equate $\displaystyle y=\frac{x}{2}$

2. Originally Posted by Punch
a) Sketch the graph of $\displaystyle y=|2cosx|+1$ for 0 ≤ x ≤ 2$\displaystyle \pi$, stating the coordinates of the turning points.

b) State the number of solutions for the equation $\displaystyle |2cosx|+1 = \frac{x}{2}$ for 0 ≤ x ≤ 2$\displaystyle \pi$
I have already solved for part a, having problems with part b...
Have you considered graphing the functions over that domain?

3. Originally Posted by Prove It
Have you considered graphing the functions over that domain?
Yes, drawing a line would solve the question. However, I do not know how to draw the line y=\frac{x}{2} on this graph...

4. Originally Posted by Punch
Yes, drawing a line would solve the question. However, I do not know how to draw the line y=\frac{x}{2} on this graph...
when x=2 , y=1

when x=4 , y=2

now you have 2 points , connect the 2 points and wherever it intersects your first function would be the solutions .

But on the x-axis is all in $\displaystyle \pi$... Do i convert $\displaystyle \pi$ to values?
But on the x-axis is all in $\displaystyle \pi$... Do i convert $\displaystyle \pi$ to values?