p = (2 , k) q = (3 , 5) Find such k that: a) p and q are orthogonal b) the angle between p and q is I was using: but somehow I can't solve it right. Thanks!
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Originally Posted by saeros p = (2 , k) q = (3 , 5) Find such k that: a) p and q are orthogonal b) the angle between p and q is I was using: but somehow I can't solve it right. Thanks! If the vectors are orthogonal, then . If the vectors are parallel, then .
I understand, but then I get to a equation I obviously can't solve ! It's like that: I guess I'm not wrong at this point.. but I have no clue how to get k out of it. Any clues please?
Hello saeros Originally Posted by saeros I understand, but then I get to a equation I obviously can't solve ! It's like that: I guess I'm not wrong at this point.. but I have no clue how to get k out of it. Any clues please? I assume it's part (b) that you're stuck with. So here it is: , when Square both sides: When you substitute back in the original equation, the negative root is invalid. So the answer is: Grandad
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