
solving trig equations
can somebody please help me
I have the question and answer to this question but i do not understand at all how the answer is concluded
Q: in the range 0<=x<=2Pi solve Sin2x=1
A:3Pi/8 and 7Pi/8
could somebody maybe briefly explain how you work this out
thanks

For angles ranging from 0 to 360,
Sin(angle) may be viewed as the y coordinate of a point on a unit circle,
of radius 1.
If 2x is the angle,
where is the y coordinate 1 ?
answer: at 270 degrees, or
Sin(270 degrees)= 1.
So 2x is 270 degrees or 270+n(360) degrees, n=0,1,2,3........
x is
The second result is obtained for 2x=270+360 degrees,
as x<360 degrees.
