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Math Help - Graphing Trig Expression help

  1. #1
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    Graphing Trig Expression help

    I need some help finding: the first local minimum point to the right of the y-axis of : y=1/2 sin(6(x-pie/4)+10

    this is what i have done
    A: 1/2
    period: 2pie/6 = pie/3
    vertical displacement: 10

    max at 10.5 min at 9.5

    i know the y is 9.5 and something gone weirdly wrong when i tired to find the x value.

    period is pie/3 so divided by 4 to find the distance between two points = pie/12

    then X= pie/3 - pie/12
    X= pie/6 this is the correct answer on the answer key , i got it right.

    further on, i tired to find the next point which is x,10. I minus pie/6 by pie/12..i got pie/6.



    Help
    how come i got another pie/6?..

    Thank You
    Last edited by hovermet; January 17th 2010 at 05:57 PM.
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  2. #2
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    Quote Originally Posted by hovermet View Post
    I need some help finding: the first local minimum point to the right of the y-axis of : y=1/2 sin(6(x-pie/4)+10

    this is what i have done
    A: 1/2
    period: 2pie/6 = pie/3
    vertical displacement: 10

    max at 10.5 min at 9.5

    i know the y is 9.5 and something gone weirdly wrong when i tired to find the x value.

    period is pie/3 so divided by 4 to find the distance between two points = pie/12

    then X= pie/3 - pie/12
    X= pie/6 this is the correct answer on the answer key , i got it right.

    further on, i tired to find the next point which is x,10. I minus pie/6 by pie/12..i got pie/6.



    Help
    how come i got another pie/6?..

    Thank You
    You are correct that y = 9.5.


    So 9.5 = \frac{1}{2}\sin{\left[6\left(x - \frac{\pi}{4}\right)\right]} + 10

    -0.5 = \frac{1}{2}\sin{\left[6\left(x - \frac{\pi}{4}\right)\right]}

    -1 = \sin{\left[6\left(x - \frac{\pi}{4}\right)\right]}

    \frac{3\pi}{2} = 6\left(x - \frac{\pi}{4}\right)

    \frac{\pi}{4} = x - \frac{\pi}{4}

    x = \frac{\pi}{2}.
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