And from that we see What do you think must be?
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Originally Posted by Prove It And from that we see What do you think must be? In fact, since the tangent function is positive in the first and third quadrants, we actually have , where is an integer representing the number of times around the unit circle. So solve .
Originally Posted by Prove It . Use the identity So This might seem a bit off track, but if you're good with your half angle identities, you will know that . Using this identity, what does equal? (It will help you solve your equation...) Taking it from here, tan2x=tan^-1\frac{1 - \cos{\theta}}{\sin{\theta}} = 15 Since tan2x=positive, it is in quadrant 1 and 3 So x=15, 195, 360+15, 360+195 = 15, 195, 375, 555
Originally Posted by Punch Taking it from here, tan2x=tan^-1\frac{1 - \cos{\theta}}{\sin{\theta}} = 15 Since tan2x=positive, it is in quadrant 1 and 3 So x=15, 195, 360+15, 360+195 = 15, 195, 375, 555 No. You have So . Also, don't try and evaluate all possibilities. Since you do not have a restricted domain, you would need an infinity of them. Just write the answer in terms of .
Oh yes, I forgot to devide it by 2 to get x values... And no, there is a domain and that is between 0 and 360
Originally Posted by Punch Find all the angles between and which satisfy the equation I thought of something and that is, does the domain of this question applies for or ?
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