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**Paymemoney** Need help on finding out what i have done wrong:

1)Solve cosec(2x)+1=2

This is what i have done

$\displaystyle cosec_(2x)=1$

$\displaystyle 2x=\frac{\pi}{2},\frac{3\pi}{2}$

$\displaystyle x=\frac{\pi}{4} and \frac{3\pi}{4}$

Answer says $\displaystyle \frac{\pi}{4} $and $\displaystyle \frac{5\pi}{4}$

2)Solve $\displaystyle cot(2x-\frac{\pi}{3})=-1$

$\displaystyle 2x=\frac{3\pi}{4}+\frac{\pi}{3}, \frac{7\pi}{4}+\frac{\pi}{3}$

$\displaystyle 2x=\frac{13\pi}{12},\frac{25\pi}{12}$

$\displaystyle x=\frac{13\pi}{24},\frac{25\pi}{24}$

P.S