Allright, just want say hi to everyone, and yes this is my first post so if I miss something go easy on me.
I need to find the value for six trig functions of angle ø, angle ø is in the second quadrant and cos(ø) = -1/√5
Am I suppose to use the unit circle on this because I did not see -1/√5 in the second quadrant?
cheers.
Step1) Draw the triangle in quad II, (check)
Step2) Find the opposite side using Pythagorean therom,
Pythagorean therom is a^2 + b^2 = c^2
-1^2 + b^2 = √5^2
1 + b^2 = 5
b^2 = 4
√b^2 = √4
b = 2
sin = o/h; 2/√5
cos = a/h; 2/-1
tan = o/a; 2/-1
sec = h/a; √5/-1
csc = h/o; √5/2
cot = a/o; -1/2
(check)
If I missed something on this feel free to correct me.
cheers.