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Math Help - Simplifying trig expression

  1. #1
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    Simplifying trig expression

    Hi
    A few question i am stuck on and need help:
    1) \frac{4sin^2(x)-4sin^4(x)}{sin(2x)}
    this is what i have done but it is incorrect.
    =\frac{4sin^2(x)(1-sin^2(x))}{sin(2x)}
    =\frac{4sin^2(x)(cos^2(x))}{2sin(x)cos(x)}
    =2sin(x)cos(x)

    2) \frac{1}{2}sin(x)cos(x)

    3) \frac{tan(x)}{1-tan^2(x)}

    P.S
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  2. #2
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    not sure what you want to simplify the expression to. im just guessing,

    1) following on,
    sin2a

    2) (1/2)sinxcosx = 1/4(2sinxcosx) = (1/4)sin2a

    3) tanx/(1-tan^2x) = 1/2[(2tanx)/(1-tan^2x)] = 1/2tan2x
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  3. #3
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    Quote Originally Posted by differentiate View Post
    not sure what you want to simplify the expression to. im just guessing,

    1) following on,
    sin2a

    2) (1/2)sinxcosx = 1/4(2sinxcosx) = (1/4)sin2a

    3) tanx/(1-tan^2x) = 1/2[(2tanx)/(1-tan^2x)] = 1/2tan2x
    yeh, thanks that makes sense now.
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