Hi A few question i am stuck on and need help: 1) this is what i have done but it is incorrect. 2) 3) P.S
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not sure what you want to simplify the expression to. im just guessing, 1) following on, sin2a 2) (1/2)sinxcosx = 1/4(2sinxcosx) = (1/4)sin2a 3) tanx/(1-tan^2x) = 1/2[(2tanx)/(1-tan^2x)] = 1/2tan2x
Originally Posted by differentiate not sure what you want to simplify the expression to. im just guessing, 1) following on, sin2a 2) (1/2)sinxcosx = 1/4(2sinxcosx) = (1/4)sin2a 3) tanx/(1-tan^2x) = 1/2[(2tanx)/(1-tan^2x)] = 1/2tan2x yeh, thanks that makes sense now.
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