Hi , I am having problems proving the identity
$\displaystyle tan^2x-sin^2x=tan^2xsin^2x$
Heres what I have done so far
[tex]
sin^2x - sin^2x(cos^2x)
cos^2x
$\displaystyle \tan^2{x} - \sin^2{x} = \frac{\sin^2{x}}{\cos^2{x}} - \sin^2{x}$
$\displaystyle = \frac{\sin^2{x} - \sin^2{x}\cos^2{x}}{\cos^2{x}}$
$\displaystyle = \frac{\sin^2{x}(1 - \cos^2{x})}{\cos^2{x}}$
$\displaystyle = \frac{\sin^2{x}\sin^2{x}}{\cos^2{x}}$
$\displaystyle = \tan^2{x}\sin^2{x}$.