Given that ,
(a) Find the exact value of
(b) solve the equation for 0< x < 180
(a) 8cos^310 - 6cos10 = 2(cos3(10))
(b) since 8cos^3x - 6cosx = 2cos 3x
2cos3x = -1
I cosine inversed but am not clear on what to do after that.
I know about the positive and negative quadrants.
However, the 3x is giving me some problems on adding and minus...
Note that 0< x <180