I need to find out "t" in the following sin^4 (t) * sec (t) = 1-[x^2/2*r^2] How do I multiply this and find the value of t?
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Originally Posted by DvdHntr I need to find out "t" in the following sin^4 (t) * sec (t) = 1-[x^2/2*r^2] How do I multiply this and find the value of t? is this your equation (was not sure what r^2 was... radius?) $\displaystyle sin^4 (t) sec (t) = 1-\frac{x^2}{2r^2} $
Last edited by bigwave; Jan 7th 2010 at 12:50 PM. Reason: spelling
r is a constant (radius) and yes that is the equation.
not sure how you can find the value of t unless x and r are first given values
x and r do not need to be given, the OP has to use trig identities such as $\displaystyle \sec(t) = \frac{1}{\cos(t)} $ on the LHS to reduce the number of times t appears.
Then I am left with: sin^4 (t) / cos (t) which is where I came from.
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