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Math Help - Applied Trigonometry Problem

  1. #1
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    Applied Trigonometry Problem


    Having a problem interpreting this question

    two forces act at a single point; force one is 20N at an angle of 15 degrees to the horizontal: force two is 30N at an angle of 40 degrees from the horizontal. Determine the magnitude and direction of the resultant of these two forces.

    should i take 15 degrees to the horizontal as 165 degrees because it is acting toward the horizontal?, i have to provide a graphical and analytical solution to the problem.

    Thanks.


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  2. #2
    Ven
    Ven is offline
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    Ok heres a picture of the problem.

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  3. #3
    MHF Contributor Calculus26's Avatar
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    There are 2 ways to approach this problem

    1. Using x and y components

    Fx = 20cos(15) - 30 cos(40) = -3.66

    Fy = -20sin(15) - 30sin(40) = -24.46

    F =sqrt(Fx^2 +Fy^2) = 25N

    theta= arctan(Fy/Fx) = 81.5 deg meaured from neg x-axis --see attachment

    2. Using Laws of Cosines and Sines

    See attachment
    Attached Thumbnails Attached Thumbnails Applied Trigonometry Problem-trig1.jpg  
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  4. #4
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    Quote Originally Posted by clayson View Post
    Having a problem interpreting this question

    two forces act at a single point; force one is 20N at an angle of 15 degrees to the horizontal: force two is 30N at an angle of 40 degrees from the horizontal. Determine the magnitude and direction of the resultant of these two forces.

    should i take 15 degrees to the horizontal as 165 degrees because it is acting toward the horizontal?, i have to provide a graphical and analytical solution to the problem.

    Thanks.


    Why not like this?
    Attached Thumbnails Attached Thumbnails Applied Trigonometry Problem-zweikraftresult.png  
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  5. #5
    MHF Contributor Calculus26's Avatar
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    Consider the direction of the forces given in the picture in the original problem.

    Otherwise I'd agree with you.
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