Hi, here's a really tough thinking question that has me totally stumped. Could someone please show me how to approach it?
Determine a sine function, F, and a cosine function, G, such that y= (squareroot of 2)sin(pi(x-2.25)) can be written in the form of F-G.
The solution at the back is:
f(x): sin(pi(x))
g(x): cos(pi(x))
I have no idea where to start...
Dear MATHDUDE2,
First you should try to simplify y= (squareroot of 2)sin(pi(x-2.25))
by using the formula, Sin(A-B)= SinACosB-SinBCosA. If you find the problem difficult please see the attachment below. Please let me know if you cannot read the attachment or if you have any problems regarding this matter.
Hope this helps.
Dear MATHDUDE2,
Do you know that Sin(2pi+A)=SinA and Cos(2pi+A)=CosA
If you do not know these trignomatic identities please refer any basic trignomatic book or the website List of trigonometric identities - Wikipedia, the free encyclopedia