this question was given on a practice test
y = sec(x)csc(x)tan(x) Determine if there are any vertical asymptotes or holes
The answer given was
Y = sin(x)/[cos(x)sin(x)] = 1/cos(x)
Therefore, there are holes at x =0, pi, 2pi, etc, and vertical asymptotes at x = pi/2, 3pi/2, etc
Should't the answer be y= 1 / cos^2(x) ?
And can someone please explain to me how you find holes in this type of function?
Thanks!