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Math Help - tan(A-B)/tan(A) + (sinC)^2/(sinA)^2=1

  1. #1
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    Question tan(A-B)/tan(A) + (sinC)^2/(sinA)^2=1

    If tan(A-B)/tan(A) + {sin(C)}^2 / {sin(A)}^2 = 1
    Then
    Show that
    tan(A).tan(B)={tan(C)}^2

    How can it be done?

    Thanks
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  2. #2
    Junior Member
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    Quote Originally Posted by sovan View Post
    tan(A).tan(B)={tan(C)}^2
    tan(A) = {tan(x)}^2/tan(B)

    Replace in the initial equation .
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  3. #3
    Super Member Bacterius's Avatar
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    Wellington
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    Quote Originally Posted by Aladdin View Post
    tan(A) = {tan(x)}^2/tan(B)

    Replace in the initial equation .
    Substituting into the original equation should work. If you could use LaTeX tags next time, it sort of helps :

    If \frac{\tan{(A-B)}}{\tan{(A)}} + \frac{\sin{(C)}^2}{\sin{(A)}^2} = 1
    Then
    Show that
    \tan{(A)} \cdot \tan{(B)} = \tan{(C)}^2

    How can it be done?

    Thanks
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