If tan(A-B)/tan(A) + {sin(C)}^2 / {sin(A)}^2 = 1

Then

Show that

tan(A).tan(B)={tan(C)}^2

How can it be done?

Thanks

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- Dec 27th 2009, 08:13 PMsovantan(A-B)/tan(A) + (sinC)^2/(sinA)^2=1
If tan(A-B)/tan(A) + {sin(C)}^2 / {sin(A)}^2 = 1

Then

Show that

tan(A).tan(B)={tan(C)}^2

How can it be done?

Thanks - Dec 27th 2009, 11:19 PMAladdin
- Dec 28th 2009, 12:29 AMBacterius
Substituting into the original equation should work. If you could use LaTeX tags next time, it sort of helps :

Quote:

If $\displaystyle \frac{\tan{(A-B)}}{\tan{(A)}} + \frac{\sin{(C)}^2}{\sin{(A)}^2} = 1$

Then

Show that

$\displaystyle \tan{(A)} \cdot \tan{(B)} = \tan{(C)}^2$

How can it be done?

Thanks