tan(A-B)/tan(A) + (sinC)^2/(sinA)^2=1

If tan(A-B)/tan(A) + {sin(C)}^2 / {sin(A)}^2 = 1
Then
Show that
tan(A).tan(B)={tan(C)}^2

How can it be done?

Thanks

Quote:

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Originally Posted by sovan

tan(A).tan(B)={tan(C)}^2

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tan(A) = {tan(x)}^2/tan(B)

Replace in the initial equation .

Quote:

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Originally Posted by Aladdin

tan(A) = {tan(x)}^2/tan(B)

Replace in the initial equation .

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Substituting into the original equation should work. If you could use LaTeX tags next time, it sort of helps :

Quote:

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If
Then
Show that


How can it be done?

Thanks

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