Hello, aargh27!
Sketch the graph of the equation: .r .= .3/(2  2·sinθ)
I know that: .r .= .3/(2  2·sinθ) .= .r .= .1.5/(1  sinθ)
and since a=1, it is a parabola. . Right!
the next step goes like: .θ .R
but how do you work that into a graph?
We already know that it's a parabola.
. . And it opens in one of four directions: left, right, up, or down.
Plot points in the four compassdirections to get its orientation.
θ = 0: . r .= .1.5/(1  0) .= .1.5
θ = π/2: . r .= .1.5/(1  1) undefined . . . The parabola opens upward.
θ = π: . r .= .1.5/(1  0) .= .1.5
θ = 3π/2: . r .= .1.5/(1  [1]) .= .0.75
This is enough to sketch the parabola. Code:

*  *

*  *

   o     +     o   
1.5  1.5
*  *
*o*
0.75
